Therefore 2M/3 of sand must be released from the balloon.
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A converging lens is used to magnify a virtual image to four times it original size. Given then focal length of the converging lens is 20.0 cm, what is the distance of the object from the lens?
m=v/u
4=v/u => v=4u
But image is virtual, so v must be negative (ie. v = -4u)
1/f = 1/u +1/v
1/f = 1/u + 1/(-4u)
1/20 = (4-1)/4u
u = 15 cm
| In this question it is important that you recognise the image is a virtual image and thus v has to be a negative number. |
The magnitude of the force created by the electric field is given by
FE = Eq
FE = EQ (using the values in this question)
The magnitude of the force created by the magnetic field is given by
FM = Bqv
FM = BQv (using the values in this question)
Q could be +ve or -ve.
If Q is +ve, then:
This could still create the motion indicated in the diagram, however FM would need to be smaller than FE.
FM < FE
BQv < EQ
v < E/Q
If Q is –ve, then:
This could still create the motion indicated in the diagram, however FM would need to be larger than FE.
FM > FE
BQv > EQ
v > E/Q
Which is answer D